Here’s how you can calculate the amount of ventilation you need. If for instance you wanted to keep you grow room temperature from getting any more than 5° warmer than the intake air temperature, and you were using 400 watts of power, you’d make the calculation below in blue. The chart is based on the following formula. It is a well-established heat transfer formula.

**(3.2 × 400) ÷ 5 = 256**
**---------------------------Calculating the passive intake.-------------------------**
**The Home Ventilating Institute recommends one square foot of open air inlet per 300 CFM of ventilation fan capacity.**
If you were going to use 256 CFM, you’d want 256/300 square feet of intake area, which is 122.88 square inches.

Here are some options for the

**intake area** for a 256 CFM ventilation fan:

1 hole - 12.5 inches in diameter.

2 holes – 8.84 inches in diameter.

3 holes – 7.22 inches in diameter.

4 holes – 6.25 inches in diameter.

5 holes – 5.59 inches in diameter.

6 holes – 5.11 inches in diameter.

Here is how to calculate the hole sizes:

1. Take the total area in square inches needed, in this case 122.88 square inches, and divide by the number of holes you want.

2. Then divide by Pi (3.14).

3. Take the square root of that value.

4. Then multiply by 2.

The answer is the diameter that each hole would need to be to make up the total area needed for intake.

A large number of small holes will create more backpressure than one large hole of equivalent area. This would be negligible unless you’re using a huge number of holes or you’re using ducting to supply the air to each intake hole. If you’re just cutting them in a wall you should be fine using 8 or less holes without having to take into account the extra backpressure.

Let me spell it out for you all, if you have a 400 watt light, multiply that times 3.2 which equals 1280 than divide by the cfm of your fan, lets assume a 500 cfm fan for this scenario, so we have 1280 divided by 500 equals 2.56

This means that using a 400 watt light and a 500 cfm fan your temp will rise 2.56 degrees above ambient temperature.

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